Math thread

[Daddy's Little Kitten]

1 + 1 = 2

 

[Just A Butt]

Just for fun I tried it with -6 and it doesn’t work.

 

[The Mass Shooter Ron Soye]

2 + 2 = 5 quick maths

 

[Monika H.]

Just for fun I tried it with -6 and it doesn’t work.
View attachment 1601329

You dork, (-7)2 doesn't give -14, but 49.
- * - = +
it's the basics of the signs.

 

[Just A Butt]

You dork, (-7)2 doesn't give -14, but 49.

Those are exponents? Where was the ^??

 

[(((Obar Lazcano Kamz)))]

no math

 

[Monika H.]

Those are exponents? Where was the ^??

Fuck. We don't use the ^ for the exponent here, I forgot.
Generally we write (-7)2 with the exponent on top. My mistake, sorry guys. I should have written it like that.

 

[Just A Butt]

Fuck. We don't use the ^ for the exponent here, I forgot.
Generally we write (-7)2 with the exponent on top. My mistake, sorry guys. I should have written it like that.

So much for math being the universal language.

 

[Yotsubaaa]

Fuck. We don't use the ^ for the exponent here, I forgot.
Generally we write (-7)2 with the exponent on top. My mistake, sorry guys. I should have written it like that.

You mean like (-7)²? Why not just type that then?

 

[Monika H.]

So much for math being the universal language.

You Americans write everything strange, even Math. You barbarians don't even use the metric system.

 

[Monika H.]

You mean like (-7)²? Why not just type that then?

HOW DID YOU DO IT.
I tried typing it like that here but I can only get (-7)2

 

[Smug Chuckler]

2 + 2 = 5 quick maths

Congrats, now you're eligible to go to Harvard.

 

[Yotsubaaa]

HOW DID YOU DO IT.
I tried typing it like that here but I can only get (-7)2

I just copy-pasted in a unicode superscript: e.g. ², ³, ⁴, ⁵, and so on.

 

[Alrakkan]

Show or disprove the following:
FOR ALL x (EXISTS y (-Q(x, (f(y)) AND (P(x) -> EXISTS y R(y)) AND P(x)) <=> FORALL x EXISTS y ((-Q(x, f(y)) AND R(y)) AND P(x))

LATEX MOTHERFUCKER DO YOU SPEAK IT

I like this proof of Euclid's Lemma a lot, especially as you can then it use to prove Unique Prime Factorisation really quickly. Source. Where a and b are elements of some set A, in general, the statement a | b means there's some c in A such that b = a*c and the statement a ∤ b is the unique statement that is true if and only if a | b is false. You're going to want to familiarise yourself with Euclidean Division if you aren't up to speed on number theory.

 

[Cyclonus]

It's maths not math, you fucking yanks. It's short for mathematics.

 

[Yotsubaaa]

Show or disprove the following:
FOR ALL x (EXISTS y (-Q(x, (f(y)) AND (P(x) -> EXISTS y R(y)) AND P(x)) <=> FORALL x EXISTS y ((-Q(x, f(y)) AND R(y)) AND P(x))

LATEX MOTHERFUCKER DO YOU SPEAK IT

Okey-dokie!

I think the brackets might be a bit iffy though (entered verbatim).

 

[Alrakkan]

Okey-dokie!
View attachment 1601419

I think the brackets might be a bit iffy though (entered verbatim).

IVE JUST BEEN DABBED ON HELP

 

[Fünter]

7

 

[Cyclonus]

Irish maths:

26 + 6 = 1

 

[Monika H.]

Simple equation
6 (3-x) + 2 (-2) (4x-2) = 14x - 6 (x-3) + 2