Parrhesia - To Speak Everything

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A lot of big posts on this thread is a shit-sperg with "intellectual" top-hats, but the fedora-wear'ers probably will never read books such as "For the Love of Physics" by Walter Lewin, because "It's not in their mindsets"
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If your going to sperg, at least spit out some logic for god sake.
 
I'm disappointed nobody has posted this the one time it applies
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anyway watching this closely until it gets put in the freezer
 
The Luigi Player said:
A lot of big posts on this thread is a shit-sperg with "intellectual" top-hats, but the fedora-wear'ers probably will never read books such as "For the Love of Physics" by Walter Lewin, because "It's not in their mindsets"
View attachment 3585782
If your going to sperg, at least spit out some logic for god sake.
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Read what this thread is about chap
Osmosis Jones said:
If you were nearly as intelligent as you believed yourself to be, you'd have realised brevity is the soul of wit and stupid people talk a lot.
Click to expand...
Read what this thread is about chap
LUNEKO said:
anyway watching this closely until it gets put in the freezer
Click to expand...
What's the freezer?, sounds cool
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Let F be an inverse square field, that is, F(r) = (c times r) divided by the length of r to the third, for some constant c where r is the vector function given by (x times i) + (y times j) + (z times k). Show that the flux of F across a sphere S with center at the origin is independent of the radius of S. So what we'll do is we'll assign a radius to a sphere S. So we'll let [variable] a be the radius of S, and then we'll see if the flux ends up not having anything to do with [variable] a. So [variable] a is the radius of S. And of course that means that the magnitude of r -- which is the square root of (x squared + y squared + z squared) is equal to - well it's equal to [variable] a, because the equation of a sphere of radius [variable] a is x squared + y squared + z squared = [variable] a squared. And so our inverse square field F(r) is equal to (c times r) over the magnitude of r to the third -- that's [variable] a to the third. So we have c over [variable] a to the third times this vector function <x, y, z>. Now what we need to do is parameterize our sphere. And we are going to do it in terms of phi and theta. So parameterizing S, we will let r(phi, theta) be equal to -- well our sphere of radius [variable] a is parameterized this way: [variable] a sine phi cosine theta in the first component function; then [variable] a sine phi sine theta; and then [variable] a cosine phi. That's what z is equal to on that sphere. And then since we have the entire sphere, we have theta -- well let's start with phi, I guess. Phi going from 0 to pi and theta going from 0 to 2 pi. So remember we are looking at a sphere of radius [variable] a; it looks something like this. And since we are going all the way around here on the xy-plane, theta goes from 0 to 2 pi. And remember phi is the angle off the positive z-axis, and so we want the entire sphere. So we want phi to be going from 0, where we are pointing straight up the positive z-axis, all the way down to phi = pi, which would mean we are pointing down the negative z-axis. So there is our parameterization. Now we want to take the flux of F across this sphere S. So what we are going to do, then, is we are going to have to take the surface integral of F over S, where S is this surface here, this parameterization. And we are going to do that, then, by integrating over this domain for our parameters: phi from 0 to pi, theta from 0 to 2 pi. Now let's just write it down here. It's going to be the double integral over, again, that domain D, of F written as a function of our parameterization r(theta) - or (phi, theta, rather) dotted with the cross products of the partial derivatives of my parameterization r sub phi cross r sub theta -- assuming that gives us the correct positive outward orientation; and I'm pretty sure it's going to. So we need to get our partial derivatives here; let's start with r sub phi. That's equal to [variable] a cosine phi cosine theta. The partial of the second component with respect to phi is [variable] a cosine phi sine theta. And then the partial of our third component with respect to phi is negative [variable] a sine phi. Take the partials of r with respect to theta, then, and we get a negative [variable] a sine phi sine theta, and then [variable] a sine phi cosine theta, and then zero for our third component. No thetas anywhere to be found in that third component function of r. Cross product time: so r sub phi cross r sub theta. i, j, and k: And let's see, we've got [variable] a cosine phi cosine theta; [variable] a cosine phi sine theta; negative [variable] a sine phi. And in the third component we have negative [variable] a sine phi sine theta; [variable] a sine phi cosine theta; and zero. So we have i times the determinant of this lower right 2-by-2: That's (zero minus a minus, or positive, [variable] a squared sine squared phi cosine theta) minus j times the determinant of the 2-by-2 we get when we block out j's column and row. That's 0 minus a (positive [variable] a squared sine squared phi sine theta). So [variable] a squared, that's - actually it's going to be minus -- let's see if we can write this correctly -- a minus [variable] a squared sine squared phi sine theta. And then plus k times the determinant of the lower left 2-by-2 matrix: And that's ([variable] a squared cosine phi sine phi cosine squared) minus a minus will make that a positive [variable] a squared cosine phi sine phi sine squared -- sine squared of theta, I should say. I should go ahead and say what my argument of my trig functions are, since we got a couple floating around here. And so our cross product is given by this vector: [variable] a squared sine phi cosine theta -- and then minus a minus makes that a positive [variable] a squared sine squared - we got it squared here, didn't I? -- sine squared phi sine theta. And then finally we can factor out an [variable] a squared cosine phi sine phi out of both of these. We are left with the cosine squared theta -- what was I saying about the arguments? -- and the sine squared theta. Cosine squared plus sine squared is 1. So we have just an [variable] a squared cosine phi sine phi for our third component function of the cross products. And you can check that this does give us the correct positive outward orientation on our surface S. So what we need to do now is write F as a function of our parameterization, r and theta. Let's come down here to do that. F((r(phi, theta)) is equal to - well we have got our constant c over [variable] a to the third out front. First component, then, is just simply x. And what is x on our parameterization? It's [variable] a sine phi cosine theta. Second component is y, which is [variable] a sine phi sine theta. And the third component, of course, is z, which is [variable] a cosine phi. So now I think we are ready to find the flux of F across S and see if it is, in fact, independent of this radius [variable] a of this sphere. So the flux of F across S is given by the dot product of these two vectors integrated over D -- dA. And so we are dotting - well let's see. We can pull our c over [variable] a to the third out front, I suppose. Well let's just take the dot product as we go here. We are taking ([variable] a sine phi cosine theta) times ([variable] a squared sine squared phi cosine theta). So we are going to have here an [variable] a to the third and sine cubed of phi, and then cosine squared theta -- plus the second components multiplied together; it's ([variable] a to the third sine cubed phi sine squared theta), and then plus ([variable] a to the third cosine cubed phi sine theta). So plus ([variable] a to the third cosine cubed phi sine theta) -- so here is what we are integrating -- dA. And before we go any further I got a sinking feeling I did something wrong here. Let's look at the product of these last two component functions again: [variable] a squared times [variable] a, that is [variable] a to the third. Cosine phi times cosine phi is just a cosine squared phi, right? So that should be a squared. And, well, sine phi - I don't see any sine thetas anywhere in my third component, so this should be a sine phi right here. So we have c over [variable] a to the third, double integral over d of - well I can factor an [variable] a to the third out of everything; that's nice. And in my first two components I can factor a sine to the third of phi out; that leaves me with the cosine squared theta plus sine squared theta, which is 1. So I have sine cubed of phi. And then plus we factor an [variable] a to the third out -- so plus a cosine squared phi sine phi. And let's go ahead then and integrate this with respect to phi and then with respect to theta. Remember phi was going from 0 to pi, and theta from 0 to 2 pi. I think the question is really going to be answered for us already. Notice that these [variable] a to the thirds divide to 1; there is no more [variable] a's anywhere to be found. So the flux is going to be independent of the radius of S. But let's go ahead and find out what that flux is in terms of c, I guess -- c is what's going to matter -- that constant. So we have c times - how about the integral from 0 to 2 pi d theta -- no thetas anywhere in our function that we are integrating. So we are going to have a 2 pi there -- times the integral from 0 to pi. Sine cubed of phi: I am going to write that as (sine of phi times sine squared, which is 1 minus cosine squared phi and then plus cosine squared phi sine phi) d phi. And when we write it that way, this becomes pretty straightforward doesn't it? I am integrating from 0 to pi. I got a (sine minus a cosine squared phi sine phi) plus a (cosine squared phi sine phi). So we are just left with sine of phi d phi. So we have (c times 2 pi) times the (antiderivative of sine), which is a negative cosine, and going from 0 to pi there -- so (c times 2 pi) times -- when I put the pi in, the cosine of pi is negative 1. So that's a negative negative 1. Minus -- putting the 0 in I get the cosine of 0, which is 1 -- so minus negative 1 again. And so we have (2 times 2 pi) times c, or 4 pi c. So we have shown that the flux across the sphere S where this F is an inverse square field is independent of the radius of S. It's just equal to (4 times pi) times that constant c.
 
Putrid fungal canal of obsessive toads
clustering the exit because they are lil tadpoles
the fountains of infinite autism
the fecal stream of madness
crystal rivers of wisdam
right beyond there boi everyone's shits mixing
fuckit invert it all inversion all
all virgins are whores are whorezs are virginz
but your mom remains a hoe
unhinged eternal bastardization of the unholy holly
Shredder
love love
glorious battle
you are such a cuck wolfe i'll fuck your wife
while you are tied up
ill let you clean her up
The catholic church is a walking dead at this point
covered in jewelry
i like that
but i also like it on the living
share or dare
glorious battle
i'll fuck your church harder than your priests fuck kids hahahaha
all the low is high all the high is low
low low low
high high high
heavy dense raaaain
a fat fat fat bitch
it's so heavy your mom's so fat and heavy it makes me start spinning around her like a lil bird
an anorexic bulimic
yes yes puke puke puke puke
it rejects the rejection she feels of being rejected by nonexistence
eject eject pus bile cum and blood
vanished

we've been subjected to vibe check
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i steal this image from another thread like i steal ya girl
put your stole on

you eat your sons in the shadows
you are fucking zombies hahahaha

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the lil maggots all dancing to the rhythm
eat your jesus faggot eat your jesus faggot mass mass hahaha
feast on your corpse maggots feast on your fish hahahahaha
drunk with the blood of the saints
drunk with the blood of the saints
wee are all drunk with the blood of the saints
hahahahahahha
I'm the son that survived and vibed
vibe check
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we've failed
our prize is eternal life
id rather pick the weird monkeys that connect andd stick to the windows ty also that sticky hand
MArriage. i spent all day on fukin chuck n cheeses all i got was these fukin monkeessss mon key

praise praise to your holy corpse
blood runs dry dry
mea culpa mea culpa
title: fu ck yu
maggots maggots maggots twirling and twisting they want to be fed fed
hharvest harvest
moon moon
hahahahahagha
the sound of the night the sound of the night
redredredredredeer

it's important to respect other people beliefs
hail the holy roman catholic apostolic church and all its saints and virgins
and masochistic sluts like Saint Theresa too
and hypocritical old skags like the other theresa as well
hail everything hail eternal hellfire hail holy honk hail anal apostasy

lest dance haha
haha i'm not a death merchant we are all dead already
dance dance
when will holy life descend again
so the lilililiiiy camps taint taint taint hahaha red like strawberry
so we feast feast hahahaa

where's your fav son
the pit is hungreeee

all fat fat juicy bountiful
jesus really filled em bellies
sow sow reap reap harvest

pig pig pig fat fat fpig
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hunger
i don't eat bro i only eat mana
Tu mana wolfe, tu mana o sea tu esposa
I love everything
borders, sorry i never got proper borders
and i'm sadomasochistic so let me hurt you
i can wash your bruises
rinse rinse
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blazin glory of insignificance3 calm down son
boom boom boom boom
kill me daddy
the harvest is reaaaadyyyyy
everyone is fukin psychoticcc
unsustainable wolfe
help your people
help us all dear jesus
THEY PISSED OFF THE FUKIN CATS YOOOO
doomed
bro but u said no more
BLOOD BLOOD BLOOD BLOOD SWORD BATTlE HOLY BATTLE GLORIOUS BATTLE HAHAHAHAH
GLORY IN HEAVEN GLORY IN HELL GLORY EVERYWHERE
ETERNAL EXHILEEEEEEEEEE FUCKKKKK YEAAHHHHHH
DRIFT DRIFT DRIFT DRIFFFFFFFTTTTT IN HOLY ENGAGEMENT
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engage negaEG ENAGAEG ENGAGE ENGAGE ENGAGE RESTRAIN. agitate your calm up
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YES DTYK DTK DTKDTKDTKDTK
DTK
DTK
DTK
\HAHAHAA YES YES
VIOLENCE VIOLENCE VIOLENCE VIOLENCE THE SMELL OF BLOOD ON WET PAVEMENT THE DUST AND THE WOUNDS AND THE BATTLE THE GLORIOUS BATTLE YES YESY YES all in good sportsmanship beating each other's shit out.
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EVERYONE EVACUATE SHITS ABOUT TO HIT THE NUMBER ONE FAN
SYNTAX IT YOURSELF FAGBROW
 
The Vatican is psychospiritual
God's Third Temple has already been built
You are the Righteous Christian Man
Die a thousand times and you won't live like the man who strikes his own path
Live a thousand lives by becoming who you are to be until you have became
 
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